Hana Piers

Although the title says jQuery  in it, I will also provide Javascript solution for this snippet. Live Demo at CodePen Suppose we have the following checkbox input: <input type="checkbox" name="colors" value="red" /> Red <input type="checkbox" name="colors" value="green" /> Green <input type="checkbox" name="colors" value="blue" /> Blue in jQuery: var colors = $('[name="colors"]'); // non-element specific var colors = $('input[name="colors"]'); // specific to "input" elements only in JavaScript: // returns array of elements with name="colors" var colors = document.getElementsByName('colors'); var colors = document.querySelectorAll('[name="colors"]'); // returns first element with name="colors" var colors = document.getElementsByName('colors')[0]; var colors = documen...

There are many ways to pass PHP variables to Javascript but I will only cover 3 most common: 1. Echo the data. 2. Use a hidden field or element. 3. Use a data attribute 1. Echo the data. The first one which is the simplest can be done as follows: var data = <?php echo $data;  ?>; But the above code can cause an issue depending on the data type and it's value, so we use json_encode to convert the data. In PHP: $name = "John O'Reily";     // a string with single quote $age = 14;                           // an integer number $address = array(                // an array     'street' => '123 Street',     'city' => 'XYZ City' ); In Javascript: var name = <?php echo json_encode($name);  ?>; var age = parseInt(<?php echo json_encode($age);  ?>); var address = <?php echo json_encode($address);  ?...

Updating your website's copyright year on annual basis can be annoying, to make your copyright year dynamically change, simply use the new Date.getFullYear(); code as shown in the example below. Live Demo  at CodePen the HTML: &copy; 1997 - <span id="currentYear"></span> // desired ouput: © 1997 - 2017 on pure Javascript: document.getElementById('currentYear').innerHTML = new Date().getFullYear(); or if you use jQuery [ CodePen demo ]: $('#currentYear').html(new Date().getFullYear());

Vagrant is a tool for building and managing virtual machine environments. Assuming you have already installed and  vagrant up your virtual environment. Execute the following instructions on your terminal console. Download symfony installer sudo curl -LsS https://symfony.com/installer -o /usr/local/bin/symfony sudo chmod a+x /usr/local/bin/symfony Create project directory symfony new my_project Then, you can: * Change your current directory to /vagrant/my_project * Configure your application in app/config/parameters.yml file. * Run your application: 1. Execute the php bin/console server:run command. 2. Browse to the http://localhost:8000 URL. * Read the documentation at http://symfony.com/doc Running #1, should produce result similar to this: php bin/console server:run [OK] Server running on http://127.0.0.1:8000 // Quit the server with CONTROL-C. If you have private network map set in Vagrantfile then do not use server:run as it only listens to http...